Are the overall odds/dynamics roughly the same if:

1. Instead of 4 dice being rolled, 3 dice are rolled instead.

2. Instead of 3 pieces advancing up the tracks, 4 pieces advance.

So you have one more piece advancing but roll only 3 dice. For the choosing values for advancing from the 3 dice it would be A+B and C+A or C+B. Example: You roll a 2, 5 and 6 and you choose to advance up the 11 spot and 8 spot. Or 11 & 7.

Thanks.

As a follow up question. What does the probability graph look like when rolling three dice, adding two together and using the third one by itself?

So 3,4,5 could be 7&5, 8&4, or 9&3.