Well then I definitely have a solution...

Die #1 - Die #2 = [0-5] => Corresponding Dual Dice.

That for SURE works. But how do you CONVERT like 3 or 4 and 5 dice into only a product of TWO (2) DICE ONLY... This IDK!

And in this context you don't NEED to remove the "6"s. Only compare dice rolls (Highest Die Roll - Lowest Die Roll.

It's not OVER-STRETCHING ... The values are all in-check. But the real issue is figuring out HOW to get 2d6s from a host of other dice...

(Continued in NEXT comment ... Maybe easier solution!)

questccgwrote:Bomber (1) > Class 4/80/8 vs. Troops (20) > Class 1/20/1

Use Dual Dice #1

Roll (Die #1) = +2/+1 [3]

=> 1 x +2/+1 = +2/+1

Results:

1x Bomber (7/8) vs. Troops (18)

***

So what I would want to ADD in terms of extra damage (DMG) is a modifier at the end if this result:

=> 1 x +2/+1 = +2/+1 [+?/+?]

***

1 <= 5 which means two (2) dice should be rolled ("6"s are removed as a failure).

So let's say I roll a "2" and a "5". What happens NEXT???

***

An IDEA: Subtract them and convert to a Dual Dice Value (1 to 6).

5 - 2 = 3 = [+2/+1]

It works because it is ONLY 2 dice being used. With more dice, I'm not sure how to handle them...

Maybe you can help me HERE???The chance for a hit with "4" is 5/6 x 5/6 x 5/6 x 5/6

You roll once, remove all the 6.

You roll once more, remove all the 6.

You roll once more again, remove all the 6.

You roll finally once more again, remove all the 6.

So... 30 might become

25 might become

19 might become

15 might become

13 might become

10

The average would be 14 to 15.

PS. I don't know what you mean with dual dice??